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@@ -0,0 +1,45 @@
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+package space.anyi;
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+
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+import java.util.Arrays;
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+import java.util.List;
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+import java.util.concurrent.CompletableFuture;
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+import java.util.stream.Collectors;
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+
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+public class Cf06_AllOfAnyOf {
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+ public static void main(String[] args) throws Exception {
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+ // 场景: 一个页面需要同时调基础信息、库存、优惠三个接口，全部返回后才渲染
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+ CompletableFuture<String> baseInfo = CompletableFuture.supplyAsync(() -> {
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+ sleep(100);
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+ return "基础信息";
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+ });
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+ CompletableFuture<String> stock = CompletableFuture.supplyAsync(() -> {
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+ sleep(200);
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+ return "库存信息";
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+ });
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+ CompletableFuture<String> coupon = CompletableFuture.supplyAsync(() -> {
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+ sleep(300);
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+ return "优惠信息";
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+ });
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+
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+ // allOf: 等全部完成(返回 Void)，再各自 join 汇总，让三路请求真正并行
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+ CompletableFuture<Void> all = CompletableFuture.allOf(baseInfo, stock, coupon);
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+ all.join();
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+ List<String> data = Arrays.stream(new CompletableFuture[]{baseInfo, stock, coupon})
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+ .map(CompletableFuture::join)
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+ .map(Object::toString)
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+ .collect(Collectors.toList());
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+ System.out.println("allOf 全部就绪，汇总结果: " + String.join(" | ", data));
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+
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+ // anyOf: 任一路先完成即返回(结果是 Object)，用于"谁先回来先给谁出结果"
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+ CompletableFuture<Object> any = CompletableFuture.anyOf(baseInfo, stock, coupon);
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+ System.out.println("anyOf 最先返回的一路: " + any.join());
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+ }
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+
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+ private static void sleep(long ms) {
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+ try {
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+ Thread.sleep(ms);
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+ } catch (InterruptedException e) {
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+ e.printStackTrace();
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+ }
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+ }
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+}
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